Comments on: Everything about MBA entrance exams…#4

By: Purushotham KT

Purushotham KT — Sat, 03 Dec 2011 08:22:38 +0000

I have done BBM..actually am very poor in english … How to improve my english laungauage sir..can u please give me a needfull suggetion pleaeeeeeeeeeeeeeeeeese sir

By: Robin Sharma

Robin Sharma — Mon, 26 Sep 2011 01:07:34 +0000

nice questions…really help full to clear basic concepts…i have attempt following :
1) ans is……….x=2 and y=3ab57
7) 42317-42/999 =42275/999
8)198 is ans

By: Vaibhav

Vaibhav — Fri, 22 May 2009 06:46:06 +0000

good explaination. amitabh why dont u try ur hands on teaching. ha ha ha…

By: Vaibhav K Mittal

Vaibhav K Mittal — Fri, 22 May 2009 06:35:55 +0000

The first 39 even perfect numbers
n = 2, 3, 5, 7, 13, 17, 19, 31, 61, 89, 107, 127, 521, 607, 1279, 2203, 2281, 3217, 4253, 4423, 9689, 9941, 11213, 19937, 21701, 23209, 44497, 86243, 110503, 132049, 216091, 756839, 859433, 1257787, 1398269, 2976221, 3021377, 6972593, 13466917 !!
This statement is wrong as most of the ones written above are odd, infact all except 1
VM

By: ajay

ajay — Fri, 15 May 2009 05:46:51 +0000

where is VM …who is gonna give answers to our queriess

By: hari prasad

hari prasad — Fri, 01 May 2009 16:39:16 +0000

1001/6 and the reminder is 5 so the 2^5 sum will be the answer.. 2^5 is 32 so 3+2=5..
the final answer is 5.

By: hariprasad from Hyd

hariprasad from Hyd — Fri, 01 May 2009 16:16:23 +0000

I got answer for 10th one — 21978.. bit trickey..

By: Hariprasad

Hariprasad — Fri, 01 May 2009 15:59:29 +0000

that is 2^6+6^2=100. so the pair is 6*2=12

By: Ansh

Ansh — Wed, 29 Apr 2009 06:50:46 +0000

Hi MTs…..VM is back in India…. he will take few days to settle …..and he will reply to all your queries very soon. By the time keep discussing …and keep shooting your queries…

By: AMITABH ANAND

AMITABH ANAND — Mon, 27 Apr 2009 11:18:55 +0000

BY THE WAY IN 10 TH Q I AM ABLE TO FIND WHT CAN BE A AND E THEY ARE2 AND 8 RESPECTIVELY

By: AMITABH ANAND

AMITABH ANAND — Mon, 27 Apr 2009 11:17:13 +0000

I M NOT SIR ANYWAY I M ALSO AN MBA ASPIRANT

By: opinionated_somehow

opinionated_somehow — Mon, 27 Apr 2009 03:27:26 +0000

thanks a lot sir!! I guess i misread the equation, I solved it for P+Q.P!! No offence i hope??????????????

By: opinionated_somehow

opinionated_somehow — Mon, 27 Apr 2009 03:25:04 +0000

thanks amithabh sir!! i think i misread the equsation!!! I solved it for p+q.p

By: amitabhanand

amitabhanand — Sun, 26 Apr 2009 15:53:58 +0000

vikas r u able to solve 10th q?

By: amitabh anand

amitabh anand — Sun, 26 Apr 2009 15:52:48 +0000

no the answers given me r the correct but the q tht i skioed ws not sure abt them

By: vikash

vikash — Sun, 26 Apr 2009 15:30:17 +0000

yaa plsss …somebody tell the correct answers ..

By: AMITABH ANAND

AMITABH ANAND — Sun, 26 Apr 2009 14:16:08 +0000

IS TEHER ANYONE WHO CAN TELL ME THE RITE ANSWER OF Q NO 10 I M NT ABLE TO SOLVE IT

By: AMITABH ANAND

AMITABH ANAND — Sun, 26 Apr 2009 13:37:48 +0000

FOR Q2 P+Q=1024 P O+1024=1024, MOMENT U COME TO KNOW BOTH R NIETHER ODD NOR EVEN BOTH ARE NON NEGATIVE IT MEANS THEY MAY BE EITHER POSITIVE OR ZERO WHICH IS A NON NEGATIVE NON POSITIVE NUMBER

By: AMITABH ANAND

AMITABH ANAND — Sun, 26 Apr 2009 13:17:31 +0000

YES FRIEND HERE IS THE EX[;ANATTION OF 8TH CAN I WRITE 0.ABABABABAB AS AB/99 SO IF THE NUMBER WITH WHICH WE MULTIPLY IT SHOULD BE A MULTIPLE OF 99 SO THT THE RESULT WILL BE A N INTEGER

FROM THE OPTION ONLY 198 IS THE MULTIPLE OF 99 SO THTS THE ANSWER

By: opinionated_somehow

opinionated_somehow — Sun, 26 Apr 2009 08:44:11 +0000

LAGTA HAI IS BAAR REPLY KE LIYE LAMBA RUKNA PADEGA !!!!!

WELCOME HOME SIR!!!
WELCOME BACK TO INDIA!!!!!!!

By: opinionated_somehow

opinionated_somehow — Sat, 25 Apr 2009 09:00:54 +0000

2^10 = 1024. 1024 = p + q. p and q both are integers. p < q. Both p and q are not even. Both p and q are not odd. None of the two is negative. What is p? What is q? YOUR ANSWER: 1024 and 0.
SIR i am kinda not in acceptance with this answer of yours!!
the condition given here is 1024 = p + q. p where p < q. Now if u choose p = 1024, then this condition is refuted.
However if p = 0, then the equation gives 1024 = 0!!
How can that be possible??
I really need an explanation on this one!!!

By: opinionated_somehow

opinionated_somehow — Sat, 25 Apr 2009 08:15:39 +0000

sir explanations!!! 2nd and 8th???

By: amitabh anand

amitabh anand — Sat, 25 Apr 2009 08:06:08 +0000

1st answer 2
2nd answer 1024 and 0
3rd answer infinity
sixth answer 2^6
seventh answer 42275/999
eighth answer 198
ninth answer 2

By: deepak

deepak — Sat, 25 Apr 2009 07:48:31 +0000

I didn't try others but I will once I get the time.

By: amitabh anand

amitabh anand — Sat, 25 Apr 2009 07:33:19 +0000

hello friends

By: opinionated_somehow

opinionated_somehow — Sat, 25 Apr 2009 02:34:27 +0000

hey deepak…………………what about other questions!! haven't tried them?? if u have !! would like to know how???????????

By: deepak

deepak — Sat, 25 Apr 2009 02:20:50 +0000

Yes, it is right. I too have done the same way. Now we are left with the final call of vaibhav sir. Sir! where are you? Give your final verdict on this solution.

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 22:45:15 +0000

1001 ^ 1001 is expanded and sum of the digits is taken. Now sum of the digits of ‘sum of the digits from previous calculation’ is taken. And so on till we get a single digit. What will be this digit?
this is one i have had enough with

lets see what i am trying to do!! STILL DONT know if i am right???? I hope masters will take care of it!!!

1001 will give the DIGITAL SUM as 2
1001^2 gives D.S. as 4
1001^3 D.S. as 8 n so on……..
Following this series 1001^1001 gives D.S. 2^1001.
now:
2^1 gives D.S.=2, 2^2 D.S.=4 n so on ……..
The system repeats after every 6th step i.e on the seventh one!! so 2^1001 gives D.S. as 2

YIPPEEEEEE!!!!

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 22:15:53 +0000

Q6: If a^b+b^a=100, where a and b are natural numbers, find the number of pairs of (a,b) such that the product a.b is maximum.(Ques by Courtesy of Mr.Rajneesh Tripathi)
still having problems with this one

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 22:07:55 +0000

DEEPAK AND VIKASH…………………..thanks guys!!! i got it , its 2!!!! i guess i had a calculation mistake!! thanks a tonn!!

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 22:00:29 +0000

How many perfect numbers are there which are greater than 100? perfect number is defined as a positive integer which is the sum of its proper positive divisors, that is, the sum of the positive divisors excluding the number itself.
Even perfect numbers are generated by the formula 2^(n−1)(2^n − 1) where n is any prime no. i guess it would be grater than 1!! for n = 2: 21(22 − 1) = 6

for n = 3: 22(23 − 1) = 28

for n = 5: 24(25 − 1) = 496

for n = 7: 26(27 − 1) = 8128.
in each instance when 2^n − 1 is a prime number, 2^(n−1)(2^n − 1) genrates a perfect number!! The first 39 even perfect numbers
n = 2, 3, 5, 7, 13, 17, 19, 31, 61, 89, 107, 127, 521, 607, 1279, 2203, 2281, 3217, 4253, 4423, 9689, 9941, 11213, 19937, 21701, 23209, 44497, 86243, 110503, 132049, 216091, 756839, 859433, 1257787, 1398269, 2976221, 3021377, 6972593, 13466917 !!

It is unknown whether there are any odd perfect numbers!!!! YAHAN KYA GALTI THI SIR?????

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 21:53:25 +0000

Q4: Give one rational number between 1.3333……. and 1.4444…….(Both are recurring decimal numbers).!!
Rational numbers are of the form p/q, q is not equal to 0; so any terminating decimal or any decimal which begins to repeat the same sequence of digits over and over.
That means i can have 1.342334233423…………… or 1.393939393939……. or 1.35 or 1.4 or 1.433333333………….!! Koi bhi choose kar lo, what was the mistake here SIR??????

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 21:47:31 +0000

Q2: 2^10 = 1024. 1024 = p + q. p and q both are integers. p < q. Both p and q are not even. Both p and q are not odd. None of the two is negative. What is p? What is q?
1..p and q both are integers. p < q
2.Both p and q are not even. Both p and q are not odd. the only possibility i get here is that one of them is even and one is odd!! according to "1024 = p + q. p"; if p is odd, then the sum will always be odd. So p is even. That means q is odd.
Now after this i am getting 4 possibilites:a) when p = 2, q becomes 1011
b.) when p = 4, q= 255
c.) p = 8, q =127
d.) p = 16, q=63
if i go further, i get p = 32, q=31 but this rules the ist condition u gave, so i have 4 coices
can u pleezzz explain on which step i went wrong!!!?????????????

By: vikash

vikash — Fri, 24 Apr 2009 18:09:37 +0000

Mine is also 2 ……is it right??

By: deepak

deepak — Fri, 24 Apr 2009 16:28:43 +0000

Sorry, for question no 9th, my answer is 2. Let me know the answer sir.

By: deepak

deepak — Fri, 24 Apr 2009 16:27:19 +0000

I am getting 2 as the answer. Is this correct sir?

By: Vaibhav Mittal

Vaibhav Mittal — Fri, 24 Apr 2009 15:55:01 +0000

wrong

By: Vaibhav Mittal

Vaibhav Mittal — Fri, 24 Apr 2009 15:54:30 +0000

Look into 8th again. If u send ur explaination, I may b able to comment. 9th is again a small concept.
Bye. VM

By: Vaibhav Mittal

Vaibhav Mittal — Fri, 24 Apr 2009 15:52:41 +0000

7th was a cool ques. Ur ans is right.
Keep going. Rajneesh

By: Vaibhav Mittal

Vaibhav Mittal — Fri, 24 Apr 2009 15:51:51 +0000

6th is a 5 second ques with common sense. without common sense 5 days are less.
All d best. Rajneesh

By: Vaibhav Mittal

Vaibhav Mittal — Fri, 24 Apr 2009 15:49:37 +0000

None of the answers except ans to Q3 is right here. Pls read the ques carefully and read what you have posted.
Thanks. VM

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 12:54:49 +0000

hey m i the only one in the country breaking my head with these problems????
9.) the ans is 5
m still confused. some from the site please help out yaar!!

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 11:12:08 +0000

9.) the ans is 0

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 10:00:47 +0000

8.) none of these, value i got is 99.
9) nahi hua sir

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 09:45:32 +0000

6) Rajneesh Sir, is question ko solve karne mein time lag raha hai!! koi short cut!! Bina technique ke bohot lamba chala jayega!!
7)Its a rational number. the p/q form – 42275/99. sorry sir i didnt take the effort to simplify it. (20 secs)

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 04:44:45 +0000

sir ans posted…………..check

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 04:11:00 +0000

sir its 8128……….please correct it upar!!!

By: opinionated_somehow

opinionated_somehow — Fri, 24 Apr 2009 04:02:57 +0000

1.) I didnt't understand the first question. M not clear bout the difference between "X" and "x". Please clear it out.
2.)1024=p+q.p. Now not both are odd, nither both are even. also P So we have possibilities:
a)p=4, q=255
b.)p=8,q=127, c.)b=16, 63
d.)p=32,q=31
so the last condition is ruled out!!
3.)Rational numbers are of the form p/q, q>0; so any terminating decimal or any decimal which begins to repeat the same sequence of digits over and over. So infinite possibilities.
4.) according to the above definition, " SIRF AAPKE LIYE", jo man kare wo choose kar lo!! 5.)perfect numbers are generated by the formula 2^(n−1)(2^n − 1). This means 2^n – 1 will always genrate a prime number. So n> 1 we have always a perfect number. 128 is one of them. the processsssss is toooooooooooooooooooooooooooooooooooooooooooooooooooo boring. you can always do it u like SIR!!

BAAKI K QUESTION BREAK KE BAAD

By: Vaibhav K Mittal

Vaibhav K Mittal — Thu, 23 Apr 2009 19:30:56 +0000

Guys and Gals. The number line I have drawn was originally in colour. Here the colours are not reflected. But I am sure you will be able to understand it without colours as well.
Looking forward to your comments.
VM