Hello All.
First of all thanks to all of you for such a great response on article 3. And second, I am sorry for being so late for the 4th article.
Before we talk of number system, lets discuss the question which I asked in comment #10 on article 3.
The answer is 10%. Let’s see how to get the answer. After explaining how to get the answer, I will give you the logic. 100-85 = 15, 100-80 = 20, 100-75 = 25, 100-70 = 30. Now 15 + 20 + 25 + 30 = 90. This 90 when subtracted from 100 is 10 which is the answer.
Logic: ————–|————————|———————————|————————————–|————–
Say this line above represents 100% of the girls. The Red ones(upto first ‘|” mark) are the ones who are not fair and therefore the balance i.e. the black ones are fair. Similarly the blue ones(from first ‘|’ mark and upto 2nd ‘|” mark) on the line do not have blue eyes. Therefore the rest i.e. red ones and black ones do have blue eyes. And similarly the yellow ones(from 2nd ‘|’ mark and upto 3rd ‘|” mark) are not tall and therefore the rest i.e. red, blue and black are tall. And similarly the green ones(from 3rd ‘|’ mark and upto 4th ‘|” mark) are not rich and therefore the rest i.e. red, blue and yellow and black, are. See carefully now, these are the black ones who have all the four characteristics. And this will be 10%.
I do not have a solution better than this. Here note that I have kept the ‘Don’t have’ disjoint to arrive at ‘have ‘at least’’. The method is useful only in this type of question. And note that this ques(with diff data) has been asked many times in last 12 CATs and many other exams. Ques: Is this Maths? No. But its common sense.
Number system comprises of rational and irrational numbers, positive and negative numbers, even and odd numbers, prime and composite numbers. It also has Natural numbers, whole numbers, Integers, Perfect numbers, co-prime numbers etc. I am assuming that all of you know all this. If not, then please read any book. Please note you will, almost always find a ques on these in CAT.
So here come a few questions for you. Real CAT type questions.
Q1: 3ab59 = x + y. x and y are natural numbers and x < y. Both x and y are prime. What is x?
Q2: 2^10 = 1024. 1024 = p + q. p and q both are integers. p < q. Both p and q are not even. Both p and q are not odd. None of the two is negative. What is p? What is q?
Q3: How many rational numbers exists between two rational numbers?
Q4: Give one rational number between 1.3333……. and 1.4444…….(Both are recurring decimal numbers).
Q5: How many perfect numbers are there which are greater than 100?
Divisibility rules: If you want to understand divisibility rules of a number, I suggest instead of mugging the things, look into the multiples of a number. You will be able to see a trend/pattern almost always. If you don’t, then keep looking for the pattern, you will for sure find a pattern, almost always. Caution: Not all the numbers have divisibility rules. But these are only few. So few that u could be effected practically. I will talk more about divisibility rules with passage of time and with your feedback.
Q6: If a^b+b^a=100, where a and b are natural numbers, find the number of pairs of (a,b) such that the product a.b is maximum.(Ques by Courtesy of Mr.Rajneesh Tripathi)
Q7. Is X = 42.317317317…….(recurring), a rational number or irrational? If it’s rational, what is it’s p/q form. (Ques by Courtesy of Mr.Rajneesh Tripathi)(I suggest in this ques note the time in which u solved this question).
Q8. X = 0.ababab………(recurring). X is multiplied by Y and the result is an integer. What can Y be?
98 b) 198 c)298 d)398 e) None of these
Q9: 1001 ^ 1001 is expanded and sum of the digits is taken. Now sum of the digits of ‘sum of the digits from previous calculation’ is taken. And so on till we get a single digit. What will be this digit?
Q10. abcde x 4 = edcba. What are a, b, c, d and e respectively. a, b, c, d and e are all distinct.
Only this much for now. I am sure all of you will be able to post the answers within 24 hours. I think that should be enough time for you for you are preparing for a 2.5 hour exam having about 75 questions.
All d best to all of you.
VM (& Rajneesh)
P.S.: Mr.Rajneesh Tripathi is a seasoned CAT trainer, teaching for last 6+ years. He is joining our team now on and will be an invaluable resource to all of you and to us as well.
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hey deepak…………………what about other questions!! haven't tried them?? if u have !! would like to know how???????????
I didn't try others but I will once I get the time.
hello friends
1st answer 2
2nd answer 1024 and 0
3rd answer infinity
sixth answer 2^6
seventh answer 42275/999
eighth answer 198
ninth answer 2
2^10 = 1024. 1024 = p + q. p and q both are integers. p < q. Both p and q are not even. Both p and q are not odd. None of the two is negative. What is p? What is q? YOUR ANSWER: 1024 and 0.
SIR i am kinda not in acceptance with this answer of yours!!
the condition given here is 1024 = p + q. p where p < q. Now if u choose p = 1024, then this condition is refuted.
However if p = 0, then the equation gives 1024 = 0!!
How can that be possible??
I really need an explanation on this one!!!
sir explanations!!! 2nd and 8th???
LAGTA HAI IS BAAR REPLY KE LIYE LAMBA RUKNA PADEGA !!!!!
WELCOME HOME SIR!!!
WELCOME BACK TO INDIA!!!!!!!
YES FRIEND HERE IS THE EX[;ANATTION OF 8TH CAN I WRITE 0.ABABABABAB AS AB/99 SO IF THE NUMBER WITH WHICH WE MULTIPLY IT SHOULD BE A MULTIPLE OF 99 SO THT THE RESULT WILL BE A N INTEGER
FROM THE OPTION ONLY 198 IS THE MULTIPLE OF 99 SO THTS THE ANSWER
FOR Q2 P+Q=1024 P<Q SO P=0 AND Q=1024
O+1024=1024, MOMENT U COME TO KNOW BOTH R NIETHER ODD NOR EVEN BOTH ARE NON NEGATIVE IT MEANS THEY MAY BE EITHER POSITIVE OR ZERO WHICH IS A NON NEGATIVE NON POSITIVE NUMBER
thanks a lot sir!! I guess i misread the equation, I solved it for P+Q.P!! No offence i hope??????????????
good explaination. amitabh why dont u try ur hands on teaching. ha ha ha…
IS TEHER ANYONE WHO CAN TELL ME THE RITE ANSWER OF Q NO 10 I M NT ABLE TO SOLVE IT
yaa plsss …somebody tell the correct answers ..
no the answers given me r the correct but the q tht i skioed ws not sure abt them
vikas r u able to solve 10th q?
I got answer for 10th one — 21978.. bit trickey..
thanks amithabh sir!! i think i misread the equsation!!! I solved it for p+q.p
I M NOT SIR ANYWAY I M ALSO AN MBA ASPIRANT
BY THE WAY IN 10 TH Q I AM ABLE TO FIND WHT CAN BE A AND E THEY ARE2 AND 8 RESPECTIVELY
Hi MTs…..VM is back in India…. he will take few days to settle …..and he will reply to all your queries very soon. By the time keep discussing …and keep shooting your queries…